x^2-12.5x+36.39=0

Solution for x^2-12.5x+36.39=0 equation:

x^2-12.5x+36.39=0

a = 1; b = -12.5; c = +36.39;
Δ = b2-4ac
Δ = -12.52-4·1·36.39
Δ = 10.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.5)-\sqrt{10.69}}{2*1}=\frac{12.5-\sqrt{10.69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.5)+\sqrt{10.69}}{2*1}=\frac{12.5+\sqrt{10.69}}{2}
$